Given that,
The equation is : 1+y=-4/5x-2
To find,
The slope of the line.
Solution,
We have,
[tex]1+y=\dfrac{-4x}{5}-2[/tex]
Subtract 1 from both sides.
[tex]1+y-1=\dfrac{-4x}{5}-2-1\\\\y=\dfrac{-4x}{5}-3[/tex] .....(2)
The general equation of line is :
[tex]y=mx+c[/tex] ...(1)
where m is slope and c is y-intercept
Comparing equation (1) and (2)
m = [tex]\dfrac{-4}{5}[/tex] and c = -3
Hence, the slope of the line is [tex]\dfrac{-4}{5}[/tex].
