5 ln(x - 2) + 8 ln(x + 3) - 3 ln(x + 8)
ln(x - 2)⁵ + ln(x + 3)⁸ - ln(x + 8)³
since [tex]a\log_cb=\log_cb^a[/tex] (for any base c)
ln((x - 2)⁵ (x + 3)⁸ / (x + 8)³)
since [tex]\log_c(a)+\log_c(b)=\log_c(ab)[/tex] and [tex]\log_c(a)-\log_c(b)=\log_c\frac ab[/tex] (also for any base c)
