Sry,i only the answer of that question no.1
(m)=1000kg
(u)=30m/s
(f)=5000n
(v)=0m/s
(a)=f/m
= 5000/1000
=5
Distance(s)=?
We know that,
V^2=u^2+2as
Or,0^2=30^2+2×5×s
Or,s=910m
So,the minium distance required to stop the car is 910m.
Hope,itwillhelpya!
