mightbegay
mightbegay mightbegay
  • 08-12-2020
  • Mathematics
contestada

PLEASE HELP!

Find the real or imaginary solutions of the following equation by factoring.

y^3 + 27 = 0

Respuesta :

mhanifa
mhanifa mhanifa
  • 09-12-2020

Answer:

  1. -3
  2. 1.5(1 + i√3)
  3. 1.5(1 - i√3)

Step-by-step explanation:

  • y³ + 27 = 0
  • (y + 3)(y² - 3y + 9) = 0

1. y + 3 = 0 ⇒

  • y = -3

2. y² - 3y + 9 = 0

  • y = (3 ±√(3² -4*9))/2
  • y = (3 ± √-27)/2
  • y = (3 ± i√27)/2
  • y = 3/2(1 ± i√3)
  • y = 1.5(1 ± i√3)
Answer Link
5927003052
5927003052 5927003052
  • 15-12-2020

Answer:

Do u still need the answer?

Step-by-step explanation:

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