Answer:
first
Step-by-step explanation:
f(n) =56 (0.5)^(n-1)
f(1) = 56 (0.5)^0= 56*1 = 56
f(2) =56 (0.5)^1 = 56* 0.5 = 28
f(3) = 56 (0.5)^2 = 14
f(4) = 56 (0.5)^3 = 7
