Respuesta :

VectorFundament120

[tex]3 \sqrt{x + 2} = \sqrt{x + 4} [/tex]

[tex](3 \sqrt{x + 2} )^{2} = ( \sqrt{x + 4} )^{2} [/tex]

[tex]9x + 18 = x + 4[/tex]

[tex]9x - x = 4 - 18[/tex]

[tex]8x = - 14[/tex]

[tex]x = - \frac{14}{8} [/tex]

[tex]x = - \frac{7}{4} [/tex]

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