pahrogers
pahrogers pahrogers
  • 07-11-2020
  • Mathematics
contestada

Rewrite the function f(x)=2(x-1)^2-1 in the form f(x)=ax^2+bx+c

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AnonymousStudent2
AnonymousStudent2 AnonymousStudent2
  • 07-11-2020

Answer:

2x^2-4x+1

Step-by-step explanation:

2(x-1)^2-1

2(x^2-2x+1)

2x^2-4x+2-1

2x^2-4x+1

Answer Link
hnori22003
hnori22003 hnori22003
  • 07-11-2020

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[tex]f(x) = 2 ({x - 1})^{2} - 1 [/tex]

[tex]f(x) = 2( {x}^{2} - 2x + 1) - 1[/tex]

[tex]f(x) = 2 {x}^{2} - 4x + 2 - 1 [/tex]

[tex]f(x) = 2 {x}^{2} - 4x + 1 [/tex]

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