Step-by-step explanation:
[tex]let \: the \: number \: be \to \: n \\ its \: resiprocal \: will \: be \: \frac{1}{n} \\ according \: to \: the \: statement \: if \:you \\ \: add \: both : you \: will \: get \: \frac{10}{3} \to\\ n + \frac{1}{n} = \frac{10}{3} \\ now \: make \:( n )\: the \: subject \: f \: the \: relationship \to \\ 3 {n}^{2} + 3 = 10n \\then : factorise \: to \: get \:( n) \\ 3 {n}^{2} - 10n + 3 =0 \\ [/tex]
