log₃(-2 tan(x)) = 1/2
Write both sides as powers of 3, and use the property [tex]b^{\log_ba}=a[/tex]:
[tex]3^{\log_3(-2\tan x)}=3^{\frac12}[/tex]
-2 tan(x) = √3
Then solve for x :
tan(x) = -√3 / 2
x = arctan(-√3 / 2) + nπ
x = -arctan(√3 / 2) + nπ
where n is any integer.
