Answer:
21.9g
Explanation:
The balanced reaction for the combustion of heptane is;
C7H16 + 11 O2 ------> 7 CO2 + 8 H2O
from the balanced reaction,
1 mole of heptane = 11 moles of O2
converting to mass
100g of Heptane = 484g of O2
xg of Heptane = 106g of O2
x = 106×100/484
x = 21.9g
Therefore, 21.9g of heptane is needed to completely react with 106 g of O2
please don't forget to mark brainliest if helpful
