vincent870 vincent870
  • 08-10-2020
  • Mathematics
contestada

What is the equation of a line in point slope form that oases trough (-2,-6) and has a slope of 1/3

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jimrgrant1 jimrgrant1
  • 08-10-2020

Answer:

y + 6 = [tex]\frac{1}{3}[/tex](x + 2)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Here m = [tex]\frac{1}{3}[/tex] and (a, b) = (- 2, - 6 ) , thus

y - (- 6) = [tex]\frac{1}{3}[/tex](x - (- 2) ) , that is

y + 6 = [tex]\frac{1}{3}[/tex](x + 2)

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