Answer:
C
Step-by-step explanation:
first, let's find the midpoint of line TR.
((x1+x2)/2, (y1+y2)/2)
(4+8)/2= x-coordinate= 6
(-4+-4)/2=y-coordinate=-4
(6,-4) is the point of A
now, use the distance formula for U (5,-6) and A (6,-4)
d= sqrt (x2-x1)^2 + (y2-y1)^2
d= sqrt (6-5)^2 + (-4-(-6))^2
d= sqrt (1+4)
d= sqrt 5
C. sqrt 5
