Answer:
D. [tex]xy\sqrt[3]{9y}[/tex]
Step-by-step explanation:
[tex]\sqrt[3]{9x^3y^4}[/tex]
[tex]\sqrt[3]{9}\sqrt[3]{x^3}\sqrt[3]{y^4}[/tex]
The [tex]\sqrt[3]{x^3}[/tex] cancels out to become x:
[tex]\sqrt[3]{9}x\sqrt[3]{y^4}[/tex]
Split the [tex]y^4=y*y^3[/tex]
[tex]\sqrt[3]{9}x\sqrt[3]{y^3}\sqrt[3]{y^1}[/tex]
[tex]\sqrt[3]{y^3} =y[/tex]
[tex]xy\sqrt[3]{9} \sqrt[3]{y}[/tex]
Put the cube root of y and cube root of 9 together:
[tex]xy\sqrt[3]{9y}[/tex]
