rutvika rutvika

08-09-2020
Mathematics

contestada

one of the factor of m^8 - 11 M ^ 4 n^ 4 - 80n^8 is

Respuesta :

mhanifa mhanifa

08-09-2020

Answer:

(m⁴ + 5n⁴)(m² + 4n²)(m + 2n)(m - 2n)

Step-by-step explanation:

See steps below:

m⁸ - 11 m⁴4 n⁴ - 80n⁸ =
(m⁴)² - (16 - 5) m⁴n⁴ - 16*5n⁸ =
(m⁴)² + 5m⁴n⁴ - 16m⁴n⁴ - 16*5n⁸ =
m⁴(m⁴ + 5n⁴) - 16n⁴(m⁴ + 5n⁴) =
(m⁴ + 5n⁴)(m⁴ - 16n⁴) =
(m⁴ + 5n⁴)(m² + 4n²)(m² - 4n²) =
(m⁴ + 5n⁴)(m² + 4n²)(m + 2n)(m - 2n)

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