Respuesta :

MichaelLiu
First, we have to notice that 0 = (2*0)^2
and 4 = (2*1)^2
and 16 = (2*3)^2
and 64 = (2*4)^2
The y value is always the square of twice the x value or,
y = (2x)^2   or   y = 4x^2