sophiesky sophiesky

09-09-2016
Mathematics

contestada

[tex] \frac{x}{x-3}- \frac{2x-1}{1} [/tex]

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apologiabiology apologiabiology

09-09-2016

get denoms the same

multiply the second equation by (x-3)/(x-3)

[tex] \frac{x}{x-3} - \frac{(2x-1)(x-3)}{(x-3)} = \frac{x-(2x-1)(x-3)}{(x-3)}= \frac{x-(2x^2-7x+3)}{(x-3)}= \frac{x-2x^2+7x-3}{(x-3)}[/tex][tex]= \frac{-2x^2+8x-3}{(x-3)}[/tex]

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