cleyol2987
cleyol2987 cleyol2987
  • 10-08-2020
  • Mathematics
contestada

32.
What is the value of x for ∆DEF?

HELP! Answer if you can!!​

32What is the value of x for DEFHELP Answer if you can class=

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Regardosfrom
Regardosfrom Regardosfrom
  • 10-08-2020

Step-by-step explanation:

[tex]c^{2} = {a}^{2} + { b}^{2} [/tex]

Pythagoras theorem

x²=12² + 5²

x²=144+25

x²=169

[tex]x = \sqrt{169} [/tex]

x=13

Answer Link
Аноним Аноним
  • 10-08-2020

Answer:

x = 13

Step-by-step explanation:

Using the Pythagorean Theorem to find the missing hypotenuse side:

[tex]a^2+b^2=c^2[/tex]

12 and 5 are a and b. 'x' would be c.

[tex]12^2+5^2=c^2\\\\12^2=144\\5^2=25\\\\144+25=c^2\\\\169=c^2\\\\\sqrt{169}=\sqrt{c^2}\\\\\boxed{13=c}[/tex]

'x' should be equal to 13.

Answer Link

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