ntcomerford ntcomerford
  • 09-08-2020
  • Mathematics
contestada

solve 27 to the power of (2/3)

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Аноним Аноним
  • 09-08-2020

Answer:

9

Step-by-step explanation:

[tex]27^{\frac{2}{3}}\\\mathrm{Factor\:the\:number:\:}\:27=3^3\\=\left(3^3\right)^{\frac{2}{3}}\\\mathrm{Apply\:exponent\:rule}:\\\\\quad \left(a^b\right)^c=a^{bc},\:\quad \:a\ge 0\\\\\left(3^3\right)^{\frac{2}{3}}=3^{3}\times \frac{2}{3}}\\\\3\=times \frac{2}{3}=2\\\\=3^2 \\\\=9[/tex]

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konrad509
konrad509 konrad509
  • 09-08-2020

[tex]27^{2/3}=(3^3)^{2/3}=3^2=9[/tex]

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