Answer:
see explanation
Step-by-step explanation:
If (2x + 1) is a factor then x = - [tex]\frac{1}{2}[/tex] is a root and P(- [tex]\frac{1}{2}[/tex] ) = 0 ← Factor theorem
P(- [tex]\frac{1}{2}[/tex] )
= 2(- [tex]\frac{1}{2}[/tex] )³ - 11(- [tex]\frac{1}{2}[/tex] )² - 4(- [tex]\frac{1}{2}[/tex] ) + 1
= - [tex]\frac{1}{4}[/tex] - [tex]\frac{11}{4}[/tex] + 2 + 1
= - [tex]\frac{12}{4}[/tex] + 3
= - 3 + 3
= 0
Since P(- [tex]\frac{1}{2}[/tex] ) = 0 then g(x) is a factor of P(x)
