QueenEsi QueenEsi

09-07-2020
Mathematics

contestada

Given that 8 <y< 12 and 1<x< 6, find the maximum possible value of
x+y/y-x

Respuesta :

devishri1977 devishri1977

09-07-2020

Answer:

Step-by-step explanation:

y = {9, 10, 11}

x = {2, 3, 4 , 5}

Maximum value of x + y = 11 + 5 = 16

Minimum value of y -x = 9 - 2 = 7

[tex]\frac{x+y}{y-x}=\frac{16}{7}[/tex]

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