Answer:
so the coordinates of mid-point of AC are (a/2,a/2)
Step-by-step explanation:
as the mid-point of AC is the same as the mid-point of BD
SO we will find the mid-point of BD
by using mid-point formula
[tex]M(x,y)=(\frac{x1+x2}{2} ,\frac{y1+y2}{2})\\M(x.y)=(\frac{0+a}{2},\frac{a+0}{2})\\ M(x,y)=(\frac{a}{2},\frac{a}{2})[/tex]
i hope this will help you :)
