Answer:
[tex]\dfrac{a+b}{a}[/tex]
Step-by-step explanation:
There is nothing to solve. Perhaps you want to simplify the expression.
[tex]\dfrac{a^{-1}+b^{-1}}{b^{-1}}=\dfrac{b(a^{-1}+b^{-1})}{b(b^{-1})}=\dfrac{b}{a}+1=\boxed{\dfrac{a+b}{a}}[/tex]
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The applicable rules of exponents are ...
b^-1 = 1/b
(a^b)(a^c) = a^(b+c)
