Answer:
0
solution,
[tex] (\frac{1}{7} ) ^{3a + 3} = {343}^{a - 1} \\ or \: ( {7}^{ - 1} ) ^{3a + 3} = {(7}^{3} ) ^{a - 1} \\ or \: (7) ^{ - 3a - 3} = {(7)}^{3a - 3} \\ or \: - 3a - 3 = 3a - 33 \\ or \: - 3a - 3a = - 3 + 3 \\ or \: - 6a = 0 \\ \: a = 0[/tex]
hope this helps..
Good luck on your assignment..
