midro0505 midro0505
  • 10-06-2020
  • Mathematics
contestada

What’s the answer I need help plssssssssss

Whats the answer I need help plssssssssss class=

Respuesta :

GrimMxReapeR
GrimMxReapeR GrimMxReapeR
  • 10-06-2020

Answer:

[tex]\frac{\sqrt[3]{19} }{\sqrt[3]{x} }[/tex]

So A is the answer

Step-by-step explanation:

[tex]y=\frac{19}{x^3}\\\mathrm{Interchange\:the\:variables}\:x\:\mathrm{and}\:y\\x=\frac{19}{y^3}\\\mathrm{Solve}\:x=\frac{19}{y^3}\:\mathrm{for}\:y\\y=\sqrt[3]{\frac{19}{x}}\\\sqrt[3]{\frac{19}{x}}\\\frac{\sqrt[3]{19} }{\sqrt[3]{x} }[/tex]

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