johnathancalderon635 johnathancalderon635
  • 09-06-2020
  • Mathematics
contestada

What is the vertex of the parabola given by y = x2 − 10x + 17? A. (5, -8) B. (-5, 8) C. (5, 8) D. (-5, -8)

Respuesta :

jimrgrant1 jimrgrant1
  • 09-06-2020

Answer:

A

Step-by-step explanation:

Given a parabola in standard form

y = ax² + bx + c ( a ≠ 0 ), then

The x- coordinate of the vertex is

[tex]x_{vertex}[/tex] = - [tex]\frac{b}{2a}[/tex]

y = x² - 10x + 17 ← is in standard form

with a = 1 and b = - 10, thus

[tex]x_{vertex}[/tex] = - [tex]\frac{-10}{2}[/tex] = 5

Substitute x = 5 into the equation for corresponding value of y

y = 5² - 10(5) + 17 = 25 - 50 + 17 = - 8

vertex = (5, - 8 ) → A

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