Answer:
a^(2m) + 2 a^m b^ (n-1) + b^ ( 2n -2)
Step-by-step explanation:
( a^m + b^(n-1) )( a^m + b^(n-1) )
FOIL
first: a^m a^m = a^ 2m
outer: a^m b^ n-1
inner a^m b^ n-1
last : b^ n-1 b^ n-1 = b^ ( 2n -2)
Add together
a^(2m) + 2 a^m b^ (n-1) + b^ ( 2n -2)
