marilyngymnast371 marilyngymnast371

06-06-2020
Chemistry

contestada

Solve for P2 when P1 = 2.0 atm V1 = 8.0 L and V2 = 32 L
This is a Boyle’s law has problem

Respuesta :

06-06-2020

P1/V1=P2/V2
2/8=x/32
X=2 multiplied by 32 divide by 8
P2=8atm

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