galal74
galal74 galal74
  • 10-05-2020
  • Mathematics
contestada

factorize 9(a+1)^2-81​

Respuesta :

chudung1976
chudung1976 chudung1976
  • 10-05-2020

Answer:

The answer is 9(a-2)(a+4).

Step-by-step explanation:

Use [tex]a^{2} -b^{2} =(a-b)(a+b)[/tex]  

[tex]9(a+1)^{2} -81= 9( (a+1)^{2}-9)= 9( (a+1)^{2}-3^{2} )= 9(a+1-3)(a+1+3)\\=9(a-2)(a+4).[/tex]

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