Answer:
no solution
Step-by-step explanation:
If we subtract the left side of the equation, we get ...
[tex]\dfrac{m^2+9}{m^2-9}-\dfrac{3}{m+3}+\dfrac{3}{3-m}=0\\\\\dfrac{m^2+9-3(m-3)-3(m+3)}{(m-3)(m+3)}=0\\\\\dfrac{m^2-6m+9}{(m-3)(m+3)}=0=\dfrac{(m-3)^2}{(m-3)(m+3)}\\\\\dfrac{m-3}{m+3}=0\quad\text{m$\ne$3}[/tex]
This equation will equal zero only if m=3, which is disallowed because it makes the denominator zero. Thus, there is no solution.
