Answer:
b=i*[tex]\sqrt{\frac{59}{11} }[/tex] or -i*[tex]\sqrt{\frac{59}{11} }[/tex]
Step-by-step explanation:
11b^2-9=-68
11b^2=-59
b^2=-59/11
b=i*[tex]\sqrt{\frac{59}{11} }[/tex] or -i*[tex]\sqrt{\frac{59}{11} }[/tex]
"i" in this case is an imaginary number, equal to [tex]\sqrt{-1\\}[/tex]
if you haven't learned about these yet, something is wrong with the question
