Answer:
2x^2+4x-2 = 2 * (x - 1 -[tex]\sqrt{2}[/tex]) * (x - 1 + [tex]\sqrt{2}[/tex])
Step-by-step explanation:
Factor completely 2x^2+4x-2
2x^2+4x-2 = 2* (x^2 + 2x - 1)
x = 1 + root( 4 - 4*(-1))/2
x = 1 + root(2)
and x = 1 - root(2)
