Respuesta :

dalendrk
n; n+1; n+2 - three consecutive whole number

n + (n + 1) + (n + 2) = 195

n + n + 1 + n + 2 = 195

3n + 3 = 195    |subtract 3 from both sides

3n = 192      |divide both sides by 3

n = 64

Answer: 64; 65; 66.
professorlopes001
HI.... Three consecutive whole number for this problem: "x-1"; "x" and "x+1", so:

x-1 + x + x+1 = 195 → 3x = 195 → x = 65.

The numbers are: 64, 65 and 66.

Thanks...

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