oliviacatalano13 oliviacatalano13
  • 09-04-2020
  • Mathematics
contestada

15. center at (-2, 0), diameter 16
equation

Respuesta :

NRMath5294 NRMath5294
  • 09-04-2020

Answer:

[tex](x+2)^{2}+y^{2}=64[/tex]

Step-by-step explanation:

The equation of a circle is given by [tex](x-h)^{2}+(y-k)^{2}=r^{2}[/tex], where [tex](h,k)[/tex] is the center and [tex]r[/tex] is the radius.

Substitute the points for [tex]h[/tex] and [tex]k[/tex] and simplify.

[tex](x-(-2))^{2}+(y-0)^{2}=r^2[/tex]

[tex](x+2)^2 + y^2 =r^2[/tex]

The diameter is given and the radius is half the length of the diameter, so the radius is 8

Substitute for [tex]r[/tex]

[tex](x+2)^2 +y^2 =8^2[/tex]

[tex](x+2)^2 +y^2 =64[/tex]

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