Answer: 33.7Ω
Explanation:
Since there are two resistors connected in series, the total resistance (Rtotal) of the circuit is the sum of each resistance.
i.e Rtotal = R1 + R2
R1 = 10Ω
R2 = 23.7Ω
Hence, Rtotal = 10Ω + 23.7Ω
Rtotal = 33.7Ω
Thus, the combined resistance for two resistors is 33.7Ω
