happybiolover happybiolover
  • 06-04-2020
  • Mathematics
contestada

answer and explain the picture above pls​

answer and explain the picture above pls class=

Respuesta :

devishri1977
devishri1977 devishri1977
  • 06-04-2020

Answer:

Step-by-step explanation:

[tex]1-\frac{sin^{2}A}{tan^{2}A}=1-\frac{sin^{2}A}{\frac{sin^{2}A}{cos^{2}A}}\\\\=1-sin^{2}A*\frac{cos^{2}A}{sin^{2}A}\\\\=1-cos^{2}A\\\\=sin^{2}A[/tex]

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