Respuesta :

konrad509
[tex]\displaystyle \binom{3}{2}\cdot\binom{4}{4}\cdot \binom{5}{2}= \dfrac{3!}{2!1!}\cdot1\cdot\dfrac{5!}{2!3!}=3\cdot1\cdot10=30 \Rightarrow D[/tex]
olemakpadu
In how many ways to choose: C = Combination

2 CDs from 3 CDs       =  ³C₂  =  (3*2)/(2*1) = 3

4 Cassettes from 4       =  ⁴C₄ = (4*3*2*1)/(4*3*2*1) = 1

2 DVDs from 5              =   ⁵C₂ = (5*4)/(2*1) = 10

Total = 3 * 1 * 10 = 30

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