Respuesta :

dalendrk
[tex]16\cdot4^{-4}=4^2\cdot4^{-4}=4^{2+(-4)}=4^{-2}=\dfrac{1}{4^2}=\boxed{\dfrac{1}{16}}\to\boxed{d.}[/tex]
vmcclain1216

Answer:

The Answer is A 1/256

Step-by-step explanation: