PeartZuliles
PeartZuliles PeartZuliles
  • 06-07-2016
  • Mathematics
contestada

using a directrix of y = 5 and a focus of (4, 1), what quadratic function is created?

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HomertheGenius
HomertheGenius HomertheGenius
  • 14-07-2016
Focus: ( 4, 1 )
Directrix: y = 5
The vertex is always half of a distance between the focus and the directrix.
The vertex must be at: ( 4, 3 ),  h = 4,  k = 3
|p| is the distance between the vertex and the directrix ( which is over the vertex and p is negative ).  p = - 2
The equation:
( x - h )² = 4 p ( y - k )  
( x - 4 )² = -8 ( y - 3 ) 
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