Answer:
x1=5/2+i
x2=5/2-i
Step-by-step explanation:
x^2-5x+7=0
a=1, b=-5, c=7
x1=(-b+sqrt(b^2-4ac))/2a
x1=(-(-5)+sqrt(5^2 - 4*1*7))/2
x1=(5+sqrt(25-28))/2
x1=(5+sqrt(-4))/2
x1=(5+sqrt(4i^2))/2
x1=(5+2i)/2
x1=5/2+i
x2=(-b-sqrt(b^2-4ac))/2a
x2=(5-2i)/2
x2=5/2-iw
