Answer:
The natural values on n is the set
{0, 1, 2, 3,4,5,6,7,8,9,10}
Step-by-step explanation:
we know that
A proper fraction is a fraction where the numerator (the top number) is less than the denominator
so
we have
[tex]\frac{n+8}{19}[/tex]
so
[tex]n+8<19[/tex]
solve for n
subtract 8 both sides
[tex]n< 19-8\\n<11[/tex]
therefore
The natural values on n is the set
{0, 1, 2, 3,4,5,6,7,8,9,10}
