Answer:
[tex]\huge\boxed{4p^2+7p+3=(p+1)(4p+3)}[/tex]
Step-by-step explanation:
[tex]4p^2+7p+3\\\\=4p^2+\underbrace{4p+3p}_{7p}+3\\\\=4p(p+1)+3(p+1)\\\\=(p+1)(4p+3)[/tex]
4p² + 7p + 3 = 4p² + 4p + 3p + 3
= 4p*(p + 1) + 3*(p + 1)
= (p + 1)(4p + 3)
