Answer:
Step-by-step explanation:
Working from the inside out, we take it one bracket at a time
2x-{3x-[x-(2x-1)]}
let's tackle the underlined prolem first
x-(2x-1)
= x-2x+1
= -x+1..we can also write this as 1-x if need be
So we now have (2x-(3x-(-x-1)))
Again, we tackle the undelined problem first
3x-(-x-1)
= 3x+x+1
= 4x+1
So we now have 2x-(4x+1)
Now we can tackle this together
= 2x-4x-1
= -2x-1
