The value of x that will make the equation true is -2
How to find the solution to an equation
Given the equation as shown below:
[tex]3^{5\sqrt{(x+2)^3}+3}=27\\3^{5\sqrt{(x+2)^3}+3} = 3^3\\{5\sqrt{(x+2)^3}+3 = 3[/tex]
Subtract 3 from both sides to have:
[tex]{5\sqrt{(x+2)^3}+3 - 3 = 3 - 3}\\{5\sqrt{(x+2)}^3=0\\(x+2)^{3/2} =0\\x+2=0\\x=-2[/tex]
Hence the value of x that will make the equation true is -2
Learn more on equations here; https://brainly.com/question/2972832
