VannahLovesGod VannahLovesGod
  • 07-02-2020
  • Mathematics
contestada

HELP ASAP WILL GIVE BRAINLIEST
Find the oblique asymptote(s).
x^2+x-5/7x^3+4x-2
y=5
y=x
y=7x
y=7
y=2

Respuesta :

sam4040
sam4040 sam4040
  • 14-02-2020

Answer:

[tex]y=7x-7[/tex]

Step-by-step explanation:

Slant asymptote: It is a non-vertical and non-horizontal line graph approaches this line but the graph never crosses it. It exists when degree of numerator is greater than that of denominator. It can be calculated by dividing numerator by denominator.

[tex]Let\ the\ function\ f(x)=\frac{7x^3+4x-2}{x^2+x-5}\\\\Then\ find\ oblique\ asymptote=(x^2+x-5)(7x-7)+(46x-37)\\\\The\ oblique\ asymptote\ (y)=7x-7[/tex]

Answer Link

Otras preguntas

which ones are wrong if the are wrong what is the right answer
The ----------------states that multiplying a sum by a number is the same as multiplying each addenda by the number and then adding the products
What was the main way that war mobilization helped to end the Great Depression?
read the scenario and answer the following questions: a. how could the scenario have been prevented? b. how should the student respond in the scenario to minimi
Alan bought a video game for $42 which was 25% off the original price what was the original price?
Was Pennsylvania founded as a haven for puritans
What is the smallest part of a compound called? element atom mixture molecule
Solving using substitution Y=4 8x-y=-12
Pleas help me with my question
How to solve x squared equals 29?