Answer:
Therefore, the constant multiple of liters in jug to the weight in kilogram is 0.62(approx)
Step-by-step explanation:
Given, Madison is carrying a 11.3 liter jug of sport drink that weights 7 kg.
Let the constant term be x
According to the problem,
11.3 × x = 7
⇔[tex]x =\frac{7}{11.3}[/tex]
⇔x = 0.62
Therefore, the constant multiple of liters in jug to the weight in kilogram is 0.62(approx)
