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10-01-2020
Chemistry

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A system performs 61 kJ of work on its surroundings and releases 107 kJ of heat. What is the change in internal energy of the system?

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gbustamantegarcia054 gbustamantegarcia054

10-01-2020

Answer:

ΔU = - 168 KJ

Explanation:

ΔU = Q + W.....................first law

∴ W = - 61 KJ........A system performs on its surroundings

∴ Q = - 107 KJ,,,,,,A system release heat

⇒ ΔU = - 107 KJ - 61 KJ = - 168 KJ

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