Answer:
[tex]y=\frac{-1}{2}x+\frac{3}{2}[/tex]
Step-by-step explanation:
Point on a line is (1,3) and (2,5).
[tex]slope=\frac{y_2-y_1}{x_2-x_1} =\frac{5-3}{2-1} =2[/tex]
slope of given line is 2
slope of perpendicular lines are negative reciprocal of one another
slope of perpendicular line is -1/2
slope = -1/2 (1,1)
[tex]y-y_1=m(x-x_1)[/tex]
[tex]y-1=\frac{-1}{2}(x-1)[/tex]
[tex]y-1=\frac{-1}{2}x+\frac{1}{2})[/tex]
add 1 on both sides
[tex]y=\frac{-1}{2}x+\frac{3}{2}[/tex]
