Answer:
-27 kJ
Step-by-step explanation:
Given data
- Initial volume (Vi): 46 L
- External pressure (P): 15 atm
We can find the work (w) associated with the expansion of a gas using the following expression.
w = - P . ΔV
w = - P . (Vf - Vi)
w = - 15 atm . (64 L - 46 L)
w = -270 atm.L . (101.325 J/ 1 atm.L)
w = -2.7 × 10⁴ J
w = -27 kJ
