For this case we have the following quadratic equation:
[tex]x ^ 2 + 7x + 9 = 3[/tex]
We must rewrite the equation as:
[tex]ax ^ 2 + bx + c = 0[/tex]
So:
Subtracting 3 from both sides of the equation we have:
[tex]x ^ 2 + 7x + 9-3 = 0\\x ^ 2 + 7x + 6 = 0[/tex]
So we have to:
[tex]a = 1\\b = 7\\c = 6[/tex]
Answer:
[tex]x ^ 2 + 7x + 6 = 0[/tex]
