Answer:
1
Step-by-step explanation:
[tex]-4i+\left(\dfrac{1}{4}-5i\right)-\left(-\dfrac{3}{4}+8i\right)+17i\\\\=-4i+\dfrac{1}{4}-5i+\dfrac{3}{4}-8i+17i\\\\=\left(\dfrac{1}{4}+\dfrac{3}{4}\right)+(-4i-5i-8i+17i)\\\\=\dfrac{1+3}{4}+(-4-5-8+17)i\\\\=\dfrac{4}{4}+0i\\\\=1[/tex]
